Topic Details (Notes format)

How to Calculate the Cross Product in 3D Vectors

Subject: Mathematics

Book: Maths Mastery

For 3D vectors u20d7A=[a₁,a₂,a₃] and u20d7B=[b₁,b₂,b₃], their cross product u20d7A×u20d7B is [a₂b₃–a₃b₂, a₃b₁–a₁b₃, a₁b₂–a₂b₁]. This new vector is perpendicular to both u20d7A and u20d7B, with magnitude = |A||B|sin(θ). Cross products are fundamental in calculating torque, normal vectors for surfaces, or rotation axes in physics. For instance, with u20d7A=[1,2,3] and u20d7B=[4,5,6], u20d7A×u20d7B=[(2×6–3×5), (3×4–1×6), (1×5–2×4)]=[12–15, 12–6, 5–8]=[–3,6,–3]. Proficiency ensures advanced 3D geometry or mechanical tasks are handled with rigor and clarity.

Practice Questions

If the average of five consecutive odd numbers is 25, what is the largest number?

View Question

If two complementary angles differ by 30°, what are the angles?

View Question

If the product of two numbers is 120 and their sum is 26, what are the numbers?

View Question

A train 120 meters long is moving at a speed of 54 km/h. How long will it take to pass a pole?

View Question

If x:y = 4:5 and y:z = 2:3, what is x:z?

View Question

What is the sum of the first 20 odd numbers?

View Question

What is the square root of 0.25?

View Question

If a square has a perimeter of 64 cm, what is its area?

View Question

If the cost price of an item is Rs. 400 and the selling price is Rs. 500, what is the profit percentage?

View Question

What is the sum of the first 10 positive even numbers?

View Question