Topic Details (Notes format)

How to Estimate Factorials Using Stirling’s Approximation

Subject: Mathematics

Book: Maths Mastery

For large n, Stirling’s Approximation n! ≈ √(2πn)(n/e)ⁿ offers a good estimate. For example, 10! = ~3,628,800, while Stirling’s gives ~3,598,700. Although approximate, it’s a vital tool in big data or theoretical analysis where direct factorial computation is cumbersome. Stirling’s bridging helps with limit evaluations, combinatorial growth rates, and advanced probability (like normal approximations to the binomial). Familiarity allows you to handle huge factorials or glean asymptotic insights into complex combinatorial expressions, beneficial in high-level math or algorithmic complexity.

Practice Questions

If x:y = 4:5 and y:z = 2:3, what is x:z?

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If two complementary angles differ by 30°, what are the angles?

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If the sum of the squares of two consecutive positive integers is 365, what are the integers?

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The sum of the squares of two consecutive integers is 145. What are the integers?

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If a cone has a radius of 5 cm and a height of 12 cm, what is its slant height?

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If the perimeter of a square is 40 cm, what is the area of the square?

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If a:b = 7:9 and b:c = 5:6, what is a:c?

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What is the 7th term of the arithmetic progression 3, 6, 9, 12,...?

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What is the sum of the interior angles of a hexagon?

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If a+b = 10 and ab = 21, what is the value of (a-b)^2?

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